While sitting on a tree branch 8.0 m above the ground, you drop a chestnut. When the chestnut has fallen 2.0 m

While sitting on a tree branch 8.0 m above the ground, you drop a chestnut. When the chestnut has fallen 2.0 m, you throw a second chestnut straight down. What initial speed must you give the second chestnut if they are both to reach the ground at the same time?

While sitting on a tree branch 8.0 m above the ground, you drop a chestnut. When the chestnut has fallen 2.0 m
this is what my physics teacher would refer to as a catch up problem.





he told us to set up so that you could look at the the ideal situation.





in this case the ideal situation would be that both chesnuts hit the ground at the same time.





so lets take a look at the first chesnut.





we have to figure out the time it would take for it to hit the ground if its 8 m above the ground and accelerates at 10m/s (9.8 if your teacher requires it) and has an initial velocity of 0.





using the second equation of kinematics x = VoT + (1/2)AT^2 u can find that the time is about 1.3 seconds.





WORK


8 = 0(t) + (1/2)(10)(t^2)


1.3 = t





So now u knwo that the second chesnut must hit the ground in 1.3 seconds as well and it must accelerate at the same rate because of gravity.





so for the second chesnut we know that it must have an acceleration of 10 m/s, a distance of 8 m and a time of 1.3 seconds.





using the second equation of kinematics u can solve for the initial velocity and get that the initial velocity is 0.38 m/s








CONGRATULATIONS IF U UNDERSTAND THIS

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